Quantum Mechanics for Engineers |
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© Leon van Dommelen |
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D.66 The triangle inequality
The normal triangle inequality continues to apply for expectation
values in quantum mechanics.
The way to show that is, like other triangle inequality proofs, rather
curious: examine the combination of , not with
, but with an arbitrary multiple of
:
For 1 this produces the expectation value of
, for 1,
the one for . In addition,
it is positive for all values of , since it consists of
expectation values of square Hermitian operators. (Just examine each
term in terms of its own eigenstates.)
If you multiply out, you get
where
,
,
and represents mixed terms that do not need to be written out. In
order for this quadratic form in to always be positive, the
discriminant must be negative:
which means, taking square roots,
and so
or
and taking square roots gives the triangle inequality.
Note that this derivation does not use any properties specific to
angular momentum and does not require the simultaneous existence of
the components. With a bit of messing around, the azimuthal quantum
number relation can be
derived from it if a unique value for exists; the key is to
recognize that where is an increasing
function of that stays below , and the values
must be half integers. This derivation is not as elegant as using the
ladder operators, but the result is the same.